InterviewSolution
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InterviewSolution
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For a reaction, `X(g) rarr Y(g) + Z(g)`. The half-life periof is `10 min`. In what periof of time would the concentration of `X` be reduced to `10%` of the original concentration ?A. `20` minB. `33` minC. `15` minD. `25` min |
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Answer» Correct Answer - B `x_((g)) rarr y_((g)) + z_((g))` The reaction is a first-order reaction hence, `K = (0.693)/(t_(1//2)) = (2.303)/(t) "log"(a)/(a-x)` `= (0.693)/(10 min)` `= (2.303)/(t) "log"(a)/(a//10)` `= (0.693)/(10) = (2.303)/(t)log 10` `t = (2.303 xx 10)/(.693) = 33 min` |
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