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For a reation: `A rarr` Product, rate law is `-(d[A])/(dt)=K[A]_(0)`. The concentration of `A` left after time `t` when `t=1/K` is:A. `([A]_(0))/(e)`B. `[A]_(0).e`C. `([A]_(0))/e^(2)`D. `1/([A]_(0))` |
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Answer» Correct Answer - a `N/N_(0)=e^(-lambdat)=e^(-lambda(1//lambda))=e^(-1)` `:. N=N_(0)/e` |
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