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For a satellite revolving close to the Earth R+H ≈ (a)R+H (b)G (c)gh (d)R |
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Answer» plz mark as brainiestExplanation:Here v is the orbital velocity of a satellite, G is the gravitational constant, r is the radius of revolution of the satellite, g is the acceleration due to gravity, M is the MASS of the earth, and R is the radius of the earth. So the TIME period of the satellite is nearly equal to 1h 24 min.plz type MANASI o sajjan in you tube and watch my VIDEO plz |
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