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For a transistor , `alpha_(dc)` and `beta_(dc)` are the current ratios, then the value of `(beta_(dc) - alpha_(dc))/(alpha_(dc) . beta_(dc))`A. 1B. 1.5C. 2D. 2.5 |
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Answer» Correct Answer - A For the transistor `beta_"dc"=alpha_"dc"/(1-alpha_"dc")` `therefore 1-alpha_(dc) = alpha_(dc)/beta_(dc)`…(1) `therefore(beta_"dc"-alpha_"dc")/(alpha_"dc"-beta_"dc")=(beta_"dc"(1-(alpha_"dc")/(beta_"dc")))/(alpha_"dc" beta_"dc")` `=(1-alpha_"dc"/beta_"dc")/alpha_"dc"` `=(1-(1-alpha_"dc"))/alpha_"dc"` ...from (1) `=alpha_"dc"/alpha_"dc"=1` ...Option (a) |
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