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For a transistor `I_(e) = 25 mA and I_(b) = 1mA`. The value of current gain `alpha` will be :-A. `(25)/(24)`B. `(24)/(25)`C. `(25)/(26)`D. `(26)/(25)` |
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Answer» Correct Answer - B `alpha=(I_(C))/(I_(E))=(I_(E)-I_(B))/(I_(E))=(25-1)/(25)=(24)/(25)` |
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