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For a Voltage divider circuit having RC=R1=R2=RE=1KΩ, if VCC=20V, find IC when Vce = VCC?(a) 1mA(b) 2mA(c) 20mA(d) 0I had been asked this question in my homework.This is a very interesting question from The Operating Point topic in division Transistor Biasing and Thermal Stabilization of Electronic Devices & Circuits

Answer» RIGHT ANSWER is (d) 0

The BEST I can EXPLAIN: when Vce = VCC,

VCC = Vce-IC (RC+RE) => VCC-Vce = 0 = IC.


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