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For all n `inN,3*5^(2n+1)+2^(3n+1)` is divisible by(A) 19 (B) 17 (C) 23 (D) 25A. 19B. 17C. 23D. 25 |
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Answer» Correct Answer - B::C Given that `3*5^(2n+1)+2^(3n+1)` For n=1, `3*5^(2(1)+1)+2^(3(1)+1` `=3*5^(3)+2^(4)` `=3xx125+16=375+16=391` Now, `391=17xx23` which is divisible by both 17 and 23. |
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