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1. |
For all sets A and B, `(A - B) uu (A nn B) = A`. |
Answer» `LHS = (A-B) uu (A nn B)` `= [ (A - B) uu A] nn [(A-B)uuB]` `= A nn (A uu B)n = A = RHS` Hence, given statement is true. |
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