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For an elementary reaction the variation of rate constant (k) with temperature is given by the following equation `log_(10) k=5.4 -100/T` Where, T is temperature on Kelvin scal and k is in terms of `sec^(-1)` Identify the incorrect options.A. There is no finite temperature at which rate constant can be `4xx10^(6) sec^(-1)`B. Fraction of activated for the reactions will be any temperatureC. Activation energy for the reaction will be approx 460.6 cal.D. Rate of reaction will vary linearly with concentration of reactant. |
Answer» Correct Answer - B |
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