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For an object projected from ground With speed uhorizontal range is two times the maximum heightattained by it. The horizontal range of object is27.2u23g3u2(2 4g4u3u2(3) 2g(4)5g |
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Answer» is the answer equal to 4u^2/5 yes but how i dont know i just used trigonometric tables for this question girik satty can u do it without using trigonometric tables? |
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