1.

For an unbiased coin how many possible outcomes are there for a coin tossed 8 times?1. \(\rm^8C_2\)2. 8!3. 284. 82

Answer» Correct Answer - Option 3 : 28

Calculation:

While tossing a coin there are 2 possible outcomes (H or T), so for every toss possible cases are multiples by factor two.

Possible cases = [(H or T), (H or T), (H or T), (H or T), (H or T), (H or T), (H or T), (H or T) , i.e.,

Total cases = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256 or 28



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