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For any sets A and B. show that `P(A nnB) = P(A)nn P(B)dot` |
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Answer» let `P(A nn B) , P(A), P(B) `are the power sets of the set `A nn B , A, B` respectively let c is a set where `C in P(A nnB)` elements of C`in (A nn B)` so, `C in A` `C in B` so, `C in P(A) & C in P(B)` `C in [ P(A) nn P(B)]` = LHS hence proved |
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