InterviewSolution
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For any three vectors `veca, vecb, vecc` the value of `[(veca+vecb,vecb+vecc,vecc+veca)]` isA. `0`B. `2[(veca, vecb, vecc)]`C. `[(veca, vecb, vecc)]`D. `-[(veca, vecb, vecc)]` |
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Answer» Correct Answer - B Let `vec(alpha)=veca+vecb, vecbeta=vecb+vecc`, and `vec(gamma)=vecc+veca`. Then `vec(alpha)=veca+vecb+0vecc,vec(beta)=0veca+vecb+vecc` and `vec(gamma)=veca+0vecb+vecc` `[(vec(alpha), vec(beta), vec(gamma))]=|(1,1,0),(0,1,1),(1,0,1)|[(veca, vecb, vecc)]` `implies[(vec(alpha), vec(beta),vec(gamma))]=2[(veca, vecb, vecc)]` |
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