InterviewSolution
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The value of `veca.(vecb+vecc)xx(veca+vecb+vecc)`, isA. `2[veca vecb vecc]`B. `[veca vecb vecc]`C. 0D. None of these |
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Answer» Correct Answer - C We have `veca+vecb+vecc=veca+(vecb+vecc)` `implies veca, vecb+vecc` and `veca+vecb+vecc` are coplanar `impliesveca.(vecb+vecc)xx(veca+vecb+vecc)=0` i.e. `[(veca, vecb+c, veca+vecb+vecc)]=0` |
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