For conductors, the free electrons will exist at(a) Valence band(b) Middle of valence and conduction band(c) Will not exist(d) Conduction bandI have been asked this question in an international level competition.The question is from Conductors in chapter Electric Fields in Material Space of Electromagnetic Theory

For conductors, the free electrons will exist at(a) Valence band(b) Mi

1.	For conductors, the free electrons will exist at(a) Valence band(b) Middle of valence and conduction band(c) Will not exist(d) Conduction bandI have been asked this question in an international level competition.The question is from Conductors in chapter Electric Fields in Material Space of Electromagnetic Theory
Answer» RIGHT choice is (d) CONDUCTION band Explanation: In conductors, the free electrons exist in the conduction band. Since the band gap energy is very low, LESS energy is required to transport the free electrons to the conduction band, as they are readily available to CONDUCT.

Discussion

No Comment Found

Related InterviewSolutions

The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air?(a) 5.14(b) 0.194(c) 63(d) 29The question was posed to me in an internship interview.My doubt stems from Boundary Conditions in section Electric Fields in Material Space of Electromagnetic Theory
A wave incident on a surface at an angle 60 degree is having field intensity of 6 units. The reflected wave is at an angle of 30 degree. Find the field intensity after reflection.(a) 9.4(b) 8.4(c) 10.4(d) 7.4I had been asked this question in exam.My doubt stems from Boundary Conditions topic in division Electric Fields in Material Space of Electromagnetic Theory
The electric flux density of a surface with permittivity of 2 is given by 12 units. What the flux density of the surface in air?(a) 24(b) 6(c) 1/6(d) 0This question was posed to me in an online quiz.My enquiry is from Boundary Conditions in portion Electric Fields in Material Space of Electromagnetic Theory
The normal component of which quantity is always discontinuous at the boundary?(a) E(b) D(c) H(d) BI got this question in class test.This interesting question is from Boundary Conditions topic in division Electric Fields in Material Space of Electromagnetic Theory
Which component of the electric field intensity is always continuous at the boundary?(a) Tangential(b) Normal(c) Horizontal(d) VerticalThe question was posed to me in an internship interview.My enquiry is from Boundary Conditions in portion Electric Fields in Material Space of Electromagnetic Theory
Find the flux density at the boundary when the charge density is given by 24 units.(a) 12(b) 24(c) 48(d) 96This question was addressed to me by my college professor while I was bunking the class.The origin of the question is Boundary Conditions in section Electric Fields in Material Space of Electromagnetic Theory
Find the electric field if the surface density at the boundary of air is 10^-9.(a) 12π(b) 24π(c) 36π(d) 48πI had been asked this question in an online interview.My question is taken from Boundary Conditions topic in division Electric Fields in Material Space of Electromagnetic Theory
For a conservative field which of the following equations holds good?(a) ∫ E.dl = 0(b) ∫ H.dl = 0(c) ∫ B.dl = 0(d) ∫ D.dl = 0I got this question in an interview.I need to ask this question from Boundary Conditions topic in section Electric Fields in Material Space of Electromagnetic Theory
The charge within a conductor will be(a) 1(b) -1(c) 0(d) ∞I have been asked this question in a job interview.Origin of the question is Boundary Conditions in portion Electric Fields in Material Space of Electromagnetic Theory
Calculate the potential when a conductor of length 2m is having an electric field of 12.3units.(a) 26.4(b) 42.6(c) 64.2(d) 24.6This question was addressed to me during an online interview.The origin of the question is Continuity Equation topic in section Electric Fields in Material Space of Electromagnetic Theory

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment