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For motion of an object along the x-axis the velocity v depends on the displacement x as `v=3x^(2)-2x`, then what is the acceleratiobn at `x=2m`.A. `48ms^(-2)`B. `80ms^(-2)`C. `18ms^(-2)`D. `10ms^(-2)` |
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Answer» Correct Answer - B Given `v=3x^(2)-2x`, differentiating v, we get `(dv)/(dt)=(6x-2)(dx)/(dt)=(6x-2)v` `impliesa=(6x-2)(3x^(2)-2x)` now put `x=2` m `impliesa=(6xx2-2)(3(2)^(2)-2xx2)=80ms^(-2)` |
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