For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as:(a) D(p, q) = [(x – s)^2 + (y – t)^2]^1/2(b) D(p, q) = |x – s| + |y – t|(c) D(p, q) = max (|x – s| + |y – t|)(d) None of the mentionedThis question was posed to me by my college professor while I was bunking the class.I want to ask this question from Relationship between Pixels and Image Enhancement Basics in section Image Enhancement of Digital Image Processing

For pixels p(x, y), q(s, t), the chessboard distance between p and q i

1.	For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as:(a) D(p, q) = [(x – s)^2 + (y – t)^2]^1/2(b) D(p, q) = \|x – s\| + \|y – t\|(c) D(p, q) = max (\|x – s\| + \|y – t\|)(d) None of the mentionedThis question was posed to me by my college professor while I was bunking the class.I want to ask this question from Relationship between Pixels and Image Enhancement Basics in section Image Enhancement of Digital Image Processing
Answer» CORRECT answer is (C) D(p, q) = max (\|X – s\| + \|y – t\|) Explanation: The chessboard distance for PIXELS p(x, y), q(s, t) is the D8 distance given by: D(p, q) = max (\|x – s\| + \|y – t\|).

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