For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:(a) D(p, q) = [(x – s)^2 + (y – t)^2]^1/2(b) D(p, q) = |x – s| + |y – t|(c) D(p, q) = max (|x – s| + |y – t|)(d) None of the mentionedI got this question by my college director while I was bunking the class.My question is from Relationship between Pixels and Image Enhancement Basics topic in division Image Enhancement of Digital Image Processing

For pixels p(x, y), q(s, t), the city-block distance between p and q i

1.	For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:(a) D(p, q) = [(x – s)^2 + (y – t)^2]^1/2(b) D(p, q) = \|x – s\| + \|y – t\|(c) D(p, q) = max (\|x – s\| + \|y – t\|)(d) None of the mentionedI got this question by my college director while I was bunking the class.My question is from Relationship between Pixels and Image Enhancement Basics topic in division Image Enhancement of Digital Image Processing
Answer» Right choice is (b) D(p, Q) = \|X – s\| + \|y – t\| For EXPLANATION: The city-block distance for PIXELS p(x, y), q(s, t) is the D4 distance given by: D(p, q) = \|x – s\| + \|y – t\|.

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