InterviewSolution
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InterviewSolution
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For reaction `aA rarr x//P`, when `[A] = 2.2 mM`, the rate was found to be `2.4mM s^(-1)`. On reducing concentration of `A` to half, the rate changes to `0.6 mM s^(-1)`. The order of reaction with respect to `A` isA. `1.5`B. `2.0`C. `2.5`D. `3.0` |
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Answer» Correct Answer - B `aA rarr xP` Rate of reaction `1= [A]^(a)` order of rection `= a` `[A]_(1) = 2.2mM, r_(1) = 2.4 mM s^(-1)` …(i) `[A]_(2) = 2.2//2 mM, r_(1) = 0.6 mM s^(-1)` or, `(2.4)/(4)` …(ii) On reducing the concetration of `A` to half, the rate of reaction is decreased by four times. Rate of reaction `= [A]^(2)` Order of reaction `= 2`. |
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