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For the arithmetic progressions write the first term a and the common difference d:0.3, 0.55, 0.80, 1.05, ………… |
Answer» Given arithmetic series 0.3, 0.55, 0.80, 1.05, ………. It is seen that, it’s of the form of a, a + d, a + 2d, a + 3d, Thus, by comparing we get, a = 0.3, a + d = 0.55, a + 2d = 0.80, a + 3d = 1.05 First term (a) = 0.3. By subtracting first term from second term. We get d = (a + d) – (a) d = 0.55 – 0.3 d = 0.25 ⇒ Common difference (d) = 0.25 |
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