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For the circuit shown, find the quiescent point.(a) (10V, 4mA)(b) (4V, 10mA)(c) (10V, 3mA)(d) (3mA, 10V)I got this question by my school principal while I was bunking the class.The above asked question is from DC Load Lines topic in section Transistor Characteristics of Electronic Devices & Circuits

Answer»

Right ANSWER is (c) (10V, 3MA)

The explanation is: We know, IE=VEE/RE=10/5kΩ=2mA

IC=α IE =IE =2mA

VCB=VCC-ICRL=20-10=10V. So, QUIESCENT point is (10V, 2mA).



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