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For the circuit shown, find the quiescent point.(a) (6V, 1mA)(b) (4V, 10mA)(c) (10V, 3mA)(d) (3mA, 10V)I have been asked this question in an interview.The origin of the question is DC Load Lines in division Transistor Characteristics of Electronic Devices & Circuits

Answer»

Correct option is (c) (10V, 3mA)

The BEST I can explain: We know, VCE=12V

(IC)SAT =VCC/RL=12/6K=2mA. IB=10V/0.5M=20µA. IC= βIB=1mA. I

VCE=VCC-ICRL=12-1*6=6V. So, quiescent point is (6V, 1mA).



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