For the circuit shown in the figure below, the Thevenin voltage and resistance looking into X-Y are __________(a) \(\frac{4}{3}\) V and 2 Ω(b) 4V and \(\frac{2}{3}\) Ω(c) \(\frac{4}{3}\) V and \(\frac{2}{3}\) Ω(d) 4 V and 2 ΩI had been asked this question by my school principal while I was bunking the class.This interesting question is from Thevenin Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory

For the circuit shown in the figure below, the Thevenin voltage and re

1.	For the circuit shown in the figure below, the Thevenin voltage and resistance looking into X-Y are __________(a) \(\frac{4}{3}\) V and 2 Ω(b) 4V and \(\frac{2}{3}\) Ω(c) \(\frac{4}{3}\) V and \(\frac{2}{3}\) Ω(d) 4 V and 2 ΩI had been asked this question by my school principal while I was bunking the class.This interesting question is from Thevenin Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory
Answer» The correct option is (d) 4 V and 2 Ω The explanation is: \(R_{TH} = \frac{V_{OC}}{I_{SC}}\) VTH = VOC Applying KCL at NODE A, \(\frac{2I-V_{TH}}{1} + 2 = I + \frac{V_{TH}}{2}\) Or, I = \(\frac{V_{TH}}{1}\) PUTTING, 2VTH – VTH + 2 = VTH + \(\frac{V_{TH}}{2}\) Or, VTH = 4 V. ∴ RTH = 4/2 = 2Ω.

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