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For the decomposition of azoisopropane to hexane and nitrogen at 54 K, the following data are obtained. Calculate the rare constant. |
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Answer» The decomposition of azoisopropane to hexane and nitrogen at 543 K is represented by the following equation. `(CH_(3))_2 CHN=NCH(CH_(3))_(2(g))toN_(2(g))+C_(6)H_(14(g))` `{:("At "t=0," "P_(0),0,0),("At "t=t,P_(0)-P,P,P):}` After time, t, total pressure, `P_(t)=(P_(0)-p)+p+p` `rarr P_(t)=P_(0)+p` `rArr p=P_(t)-P_(0)` Therefore, `P_(0)-p=P_(0)-(P_(0)-P_(0))` `=2P_(0)-P_(t)` For a first order reaction, `k =2.303/t"log"(P_(0))/(P_(0)-P)` ` =2.303/t"log"(P_(0))/(2P_(0)-P_(t))` When `t =360 s_(1),` ` k=(2.303)/(720" s")"log" (35.0)/(2xx35.0-63.0)` When t `720 s_(1)` =`2.235xx10^(-3)s^(-1)` Hence, the average value of rate constant is `k=((2.175xx10^(-3))+(2.35xx10^(-3)))/2s^(-1)` ` 2.21xx10^(-3)s^(-1)` Note: There is a slight variation in this answer and the one given in the NCERT textbook. |
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