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For the equation `cos^(-1)x+cos^(-1)2x+pi=0`, the number of real solution isA. 1B. 2C. 0D. `oo` |
Answer» Correct Answer - C We have `cos^(-1) x + cos^(-1) (2x) = -pi`, which is not possible as `cos^(-1) x and cos^(-1) 2x` never take negative values |
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