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For the equilibrium, `A(g) rarr B(g) , DeltaH` is -40 KJ/mol. If the ratio of the activation energies of the forward `(E_(f))` and reverse `(E_(b))` reactions is `(2)/(3)` then:A. `E_(f)` =60 KJ/mol, `E_(b)`=100 KJ/molB. `E_(f)` =30 KJ/mol, `E_(b)`=70 KJ/molC. `E_(f)` =80 KJ/mol, `E_(b)`=120 KJ/molD. `E_(f)` =70 KJ/mol, `E_(b)`=30 KJ/mol |
Answer» Correct Answer - C |
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