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For the first order reaction, calculate the ratio of the time taken to complete `99%` of the reaction to the time taken to complete `90%` of the reaction. |
Answer» `t=(2.303)/k log a/(a-x)` `t_(99%) = (2.303)/k log (100)/1=2.303/k xx 2 = 4.606/k` `t_(90%) = (2.303)/k log 100/10 = 2.303/k xx 1=2.303/k` `t_(99%)/t_(90%)=4.606/2.303 = 2`. |
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