1.

For the first order reaction, calculate the ratio of the time taken to complete `99%` of the reaction to the time taken to complete `90%` of the reaction.

Answer» `t=(2.303)/k log a/(a-x)`
`t_(99%) = (2.303)/k log (100)/1=2.303/k xx 2 = 4.606/k`
`t_(90%) = (2.303)/k log 100/10 = 2.303/k xx 1=2.303/k`
`t_(99%)/t_(90%)=4.606/2.303 = 2`.


Discussion

No Comment Found

Related InterviewSolutions