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For the given reaction, `CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l)` Select the correct option for `Delta_(r)H`.A. `[H_(m)(CO_(2),g)+2H_(m)(O_(2),g)]-[2H_(m)(H_(2)O,l)+H_(m)(CH_(4),g)]`B. `[2H_(m)(O_(2),g)+H_(m)(CH_(4),g)]-[H_(m)(CO_(2),g)+2H_(m)(H_(2)O,l)]`C. `[H_(m)(CO_(2),g)+2H_(m)(H_(2)O,l)]-[H_(m)(CH_(4),g)+2H_(m)(O_(2),g)]`D. `[H_(m)(CO_(2),g)+H_(m)(H_(2)O,l)]-[H_(m)(CH_(4),g)+2H_(m)(O_(2),g)]` |
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Answer» Correct Answer - C `CH_(4)(g)+2O_(2)(g) to CO_(2)(g)+2H_(2)O(l)` `Delta_(r)H=underset(i)(sum)sigma_(i)H_("products")-underset(i)(sum)sigma_(i)H_("reactants")` `=[H_(m)(CO_(2),g)+2H_(m)(H_(2)O,l)]-[H_(m)(CH_(4),g)+2H_(m)(O_(2),g)]` where, `H_(m)` is the molar enthalpy. |
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