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For the network shown in the figure, the value of the current9V3518V305V5V18ŕšŕ¸ |
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Answer» As 4/6= 2/3so middle resistance will be removedBecause of balance bridgeso now4+2//6+3= 6//9= 6*9/15= 54/15 total resistancenow I= V/R= V/54/15= 15V/54= 5V/18 |
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