InterviewSolution
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InterviewSolution
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For the non-stoichiometric reaction `2A+BrarrC+D` The following kinetic data were obtained in theee separate experiment, all at `98 K` `|{:("Initial concentration (A)","Initial concentration (B)","Initial rate of formation of C" (molL^(-1) s^(-1))),(0.1 M,0.1 M,1.2 xx 10^(-3)),(0.1 M,0.2 M,1.2 xx 10^(-3)),(0.2 M,0.1 M,2.4 xx 10^(-3)):}|` The rate law for the formation of `C` is:A. `(dc)/(dt)=k[A][B]^(2)`B. `(dc)/(dt)=k[A]`C. `(dc)/(dt)=k[A][B]`D. `(dc)/(dt)=k[A]^(2)[B]` |
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Answer» Correct Answer - B Let order with respect to A and B are `alpha and beta` resepecitvely `:. (dc)/(dt)=k[A]^(alpha)[B]^(beta)` `1.2xx10^(-3)=k[0.1]^(alpha)[0.1]^(beta)" ".....(i)` `1.2xx10^(-3)=k[0.1]^(alpha)[0.2]^(beta)" ".....(ii)` `2.4xx10^(-3)=k[0.2]^(alpha)[0.1]^(beta)" ".....(iii)` `{:("Dividing (ii) by (i)":,2^(beta),:.beta=0),("Dividing (ii)by(i)":,2^(alpha)=2,:.alpha1),("Rate law will be ":,,):}` `(dc)/(dt)=k[A]` |
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