1.

For the reaction `2 N_(2) O_(5(g)) to 4 NO_(2 (g)) to O_(2(g))` , if concentration of `NO_(2)` in 100 seconds is increased by `5.2 xx 10^(-3)` m . Then the rate of reaction will beA. `1.3 xx 10^(-5) ms^(-1)`B. `5 xx 10^(-4) ms^(-1)`C. `7.6 xx 10^(-4) ms^(-1)`D. `2 xx 10^(-3) ms^(-1)`

Answer» Correct Answer - a
`2N_(2)O_(5(g)) to 4NO_(2 (g)) + O_(2(g))`
Rate of reaction with respect to `NO_(2)`
`=(1)/(4) (d[NO_(2)])/(dt) = (1)/(4) xx (5.2 xx 10^(-3))/(100) = 1.3 xx 10^(-5) ms^(-1)`.


Discussion

No Comment Found

Related InterviewSolutions