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For the reaction `2N_(2)O_(5)rarr 4NO_(2)+O_(2)`, if rate formation of `O_(2) is 16 g//hr`, then rate of decomposition of `N_(2)O_(5)` and rate of formation of `NO_(2)` respectively is:A. `54 g//hr and 46 g//hr`B. `32 g//hr and 64 g//hr`C. `108 g//hr and 92 g//hr`D. None of these |
Answer» Correct Answer - c `(d[O_(2)])/(dt)=16 g//hr=16/32 mol//hr` `(d[NO_(2)])/(dt)=(4d[O_(2)])/(dt)=4xx16/32=2 mol//hr` `=2xx46=92 g//hr` `(-d[N_(2)O_(5)])/(dt)=(2d[O_(2)])/(dt)=2xx16/32=1 mol//hr` `=1xx108=108 g//hr` |
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