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For the reaction `2N_(2)O_(5) rarr 4NO_(2)+O_(2)` rate of reaction and rate constant are `1.02 xx 10^(-4)` and `3.4 xx 10^(-5) sec^(-1)` respectively. The concentration of `N_(2)O_(5)` at that time will beA. `1.732`B. `3`C. `1.02xx10^(-4)`D. `3.4xx10^(5)` |
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Answer» Correct Answer - B The reaction `2N_(2)O_(5)rar4NO_(2)+O_(2)` is a first order reaction (Look at the unit of the unit of rate constant). Thus Rate `=k[N_(2)O_(5)]` `[N)_(2)O_(5)]=(Rate)/(k)` `=(1.02xx10^(-4)molL^(-1_s^(-1))/(3.4xx10^(-5)s^(-1))` `=3.0molL^(-1)` |
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