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For the reaction `2N_(2)O_(5) rarr 4NO_(2)+O_(2)` rate of reaction and rate constant are `1.02 xx 10^(-4)` and `3.4 xx 10^(-5) sec^(-1)` respectively. The concentration of `N_(2)O_(5)` at that time will beA. 1.732B. 3C. `1.02 xx 10^(-4)`D. `3.4 xx 10^(5)` |
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Answer» Correct Answer - B b) `[N_(2)O_(5)]= ("Rate")/k = (1.2 xx 10^(-4) mol L^(-1)s^(-1))/(3.4 xx 10^(-5)s^(-1))`=3 |
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