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For the reaction `2N_(2)O_(5) rarr 4NO_(2)+O_(2)` rate of reaction and rate constant are `1.02 xx 10^(-4)` and `3.4 xx 10^(-5) sec^(-1)` respectively. The concentration of `N_(2)O_(5)` at that time will beA. `1.732`B. `3`C. `1.02 xx 10^(-4)`D. `3.4 xx 10^(5)` |
Answer» Correct Answer - B `R = K[A], 1.02 xx 10^(-4) = 3.4 xx 10^(-5), [N_(2)O_(5)]` or `(N_(2)O_(5)) = (1.02 xx 10^(-4))/(3.4 xx 10^(-5)), K = 3` |
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