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For the reaction `2NO(g) + H_(2)(g) rarr N_(2)O(g) + H_(2)O(g)`, at `900 K` following data are observed. `{:("Initial pressure of NO (atm)","Initial pressure of" H_(2)o (atm),"Initial rate of pressure decrease" (atm min^(-1))),(0.150,0.40,0.020),(0.075,0.40,0.005),(0.150,0.20,0.010):}` Find the order of reaction.A. `3`B. `2`C. `1`D. `0` |
Answer» Correct Answer - A form experiments `I` and `II, [H_(2)]` is constant and `[NO]` is doubled. Then rate becomes `4` times. So order of reaction w.r.t. `(NO) = 2`. form experiments `I` and `III, [NO]` is constant, and `[H_(2)]` is doubled then rate becomes `2` times. So order of reaction w.r.t. `(H_(2)) = 1`. Total order `= 3`. Hence answer (a) is correct. |
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