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For the reaction `4NH_(3) + 5O_(2) to 4NO + 6H_(2) O`, if the rate of disappearance of `NH_(3)` is `3.6 xx 10^(-3)` mol `L^(-1) s^(-1)`, what is the rate of formation of `H_(2) O`A. `5.4xx10^(-3) mol L^(-1)s^(-1)`B. `3.6xx10^(-3)mol L^(-1)s^(-1) `C.D. |
Answer» Correct Answer - A `-(1)/(4) (d[NH_(3)])/(dt) =+(1)/(6) (d[H_(2)O])/(dt) ` ` (d[H_(2)O])/(dt) =(6)/(4)xx3.6xx10^(-3) =5.4xx10^(-3) mol L^(-1)S^(-1)` |
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