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InterviewSolution
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For the reaction `A + 2B rarr` products (started with concentration taken in stoichiometric proportion), the experimentally determined rate law is : `-(d[A])/(d t) = ksqrt([A])sqrt([B])` The half life time of the reaction would be :A. `(0.693)/(k)`B. `(0.693)/(1//k)`C. `(0.693)/(sqrt(2k))`D. not defined |
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Answer» Correct Answer - C `{:(A,+,,2B rarr,"products"),(a-x,,,2a - 2x,):}` `- (d[A])/(d t) = ksqrt([A])sqrt([B])` Reactant are in their stoichiometric proportional `rArr -(d(a-x))/(d t) = k = sqrt((a-x)) sqrt(2(a-x))` `(d x)/(d t) = sqrt(2)k (a-x)" "t_(1//2) = (0.693)/(sqrt(2)k)` |
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