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For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction is expressed asA. `-(Delta[I_(2)])/(Delta t) = - (Delta[H_(2)])/(Delta t) = (1)/(2)(Delta[HI])/(Delta t)`B. `(Delta[I_(2)])/(Delta t) = - (Delta[H_(2)])/(Delta t) = (Delta[HI])/(2Delta t)`C. `(Delta[H_(2)])/(Delta t) = (1)/(2) (Delta[I_(2)])/(Delta t) = -(Delta[HI])/(Delta t)`D. None of these |
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Answer» Correct Answer - A For given reaction: `-(Delta[I_(2)])/(Delta t) = -(Delta[H_(2)])/(Delta t) = (1)/(2) (Delta[HI])/(Delta t)` |
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