For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction is expressed asA. (a) `(-d[H_(2)])/(dt)=(-d[I_(2)])/(dt)=(-d[HI])/(dt)`B. (b) `(d[H_(2)])/(dt)=(d[I_(2)])/(dt)=(d[HI])/(dt)`C. (c ) `1/2 (d[H_(2)])/(dt)=1/2(d[I_(2)])/(dt)=(-d[HI])/(dt)`D. (d) `-2(d[H_(2)])/(dt)=-2(d[I_(2)])/(dt)=(d[HI])/(dt)`

For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction

1.	For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction is expressed asA. (a) `(-d[H_(2)])/(dt)=(-d[I_(2)])/(dt)=(-d[HI])/(dt)`B. (b) `(d[H_(2)])/(dt)=(d[I_(2)])/(dt)=(d[HI])/(dt)`C. (c ) `1/2 (d[H_(2)])/(dt)=1/2(d[I_(2)])/(dt)=(-d[HI])/(dt)`D. (d) `-2(d[H_(2)])/(dt)=-2(d[I_(2)])/(dt)=(d[HI])/(dt)`
Answer» Correct Answer - d `(d[H_(2)])/(dt)=(-d[I_(2)])/(dt)=1/2(d[HI])/(dt)`

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