1.

For the reaction `N_(2)+3H_(2) rarr 2NH_(3)`, if `(d[NH_(3)])/(dt).=4xx10^(-4)` mol `L^(-1)s^(-1)`, the value of `(-d[H_(2)])/(dt)` would beA. `3xx10^(-4) mol L^(-1)S^(-1)`B. `4xx10^(-4) mol L^(-1)S^(-1)`C. `6xx10^(-4) mol L^(-1)S^(-1)`D. `1xx10^(-4) mol L^(-1)S^(-1)`

Answer» Correct Answer - A
For the reaction ,
`N_(2)+3H_(2) to NH_(3)`
`rate =-(d[N_(2)])/(dt)=-(1)/(3)(d[H_(2)])/(dt)=+(1)/(2) (d[NH_(3)])/(dt)`
`or -(1)/(3)(d[H_(2)])/(dt)=+(d[NH_(3)])/(dty)`
`-(d[H_(2)])/(dt)=(3)/(2)xx2xx10^(-04)molL^(-1)S^(-1)`
`=3xx10^(-4)molL^(-1)S^(-1)`


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