InterviewSolution
Saved Bookmarks
| 1. |
For the reaction `N_(2) + 3H_(2) to 2NH_(3)` if `(Delta[NH_(3)])/(Deltat) = 2 xx 10^(-4) mol L^(-1)s^(-1)`, the value of `(-Delta[H_(2)])/(Deltat)` would beA. `1 xx 10^(-3) mol L^(-1)s^(-1)`B. `3 xx 10^(-4)molL^(-1)s^(-1)`C. `4 xx 10^(-4) mol L^(-1)s^(-1)`D. `6 xx 10^(-4)molL^(-1)s^(-1)` |
|
Answer» Correct Answer - B b) `(-Delta[H_(2)])/(Deltat) = 3//2 xx 2 xx 10^(-4) mol L^(-1)s^(-1)` `=3 xx 10^(4) mol L^(-1)s^(-1)` |
|