1.

For the reaction `N_(2) + 3H_(2) to 2NH_(3)` if `(Delta[NH_(3)])/(Deltat) = 2 xx 10^(-4) mol L^(-1)s^(-1)`, the value of `(-Delta[H_(2)])/(Deltat)` would beA. `1 xx 10^(-3) mol L^(-1)s^(-1)`B. `3 xx 10^(-4)molL^(-1)s^(-1)`C. `4 xx 10^(-4) mol L^(-1)s^(-1)`D. `6 xx 10^(-4)molL^(-1)s^(-1)`

Answer» Correct Answer - B
b) `(-Delta[H_(2)])/(Deltat) = 3//2 xx 2 xx 10^(-4) mol L^(-1)s^(-1)`
`=3 xx 10^(4) mol L^(-1)s^(-1)`


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