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For the reaction, `N_(2)O_(5) rarr 2NO_(2)+1/2O_(2), Given` `-(d[N_(2)O_(5)])/(dt)=K_(1)[NO_(2)O_(5)]` `(d[NO_(2)])/(dt)=K_(2)[N_(2)O_(5)] and (d[O_(2)])/(dt)=K_(3)[N_(2)O_(5)]` The relation in between `K_(1), K_(2)` and `K_(3)` is:A. `2K_(1)=K_(2)=4K_(3)`B. `K_(1)=K_(2)=K_(3)`C. `2K_(1)=4K_(2)=K_(3)`D. None of these |
Answer» Correct Answer - a `(-d[N_(2)O_(5)])/(dt)=1/2(d[NO_(2)])/(dt)=(2d[O_(2)])/(dt)` `:. K_(1)[N_(2)O_(5)]=K_(2)/2[N_(2)O_(5)]=2K_(3)[N_(2)O_(5)]` |
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