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For the reaction `NO_(2)+COrarrCO_(2)+NO`, the experimental rate expresison is `-dc//dt = k[NO_(2)]^(2)`. Find the number of molecules of `CO` involved in the slowest step.A. `0`B. `1`C. `2`D. `3` |
Answer» Correct Answer - A Since there is no `[CO]` involved in rate expression therefore `CO` is involved in fast step. |
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