1.

For the reaction `NO_(2)+COrarrCO_(2)+NO`, the experimental rate expresison is `-dc//dt = k[NO_(2)]^(2)`. Find the number of molecules of `CO` involved in the slowest step.A. `0`B. `1`C. `2`D. `3`

Answer» Correct Answer - A
Since there is no `[CO]` involved in rate expression therefore `CO` is involved in fast step.


Discussion

No Comment Found

Related InterviewSolutions