For the reaction, `X_(2)O_(4)(l)rarr2XO_(2)(g),DeltaE=2.1Kcal` , `DeltaS=20cal//K` at `300K` . Hence `DeltaG` isA. `2.7 kcal`B. `-2.7 kcal`C. `9.3 kcal`D. `-9.3 kcal`

For the reaction, `X_(2)O_(4)(l)rarr2XO_(2)(g),DeltaE=2.1Kcal` , `Delt

1.	For the reaction, `X_(2)O_(4)(l)rarr2XO_(2)(g),DeltaE=2.1Kcal` , `DeltaS=20cal//K` at `300K` . Hence `DeltaG` isA. `2.7 kcal`B. `-2.7 kcal`C. `9.3 kcal`D. `-9.3 kcal`
Answer» `DeltaH = DeltaU +Deltan_(g)RT` `= 2.1 xx2xx 0.02 xx 300 = 3.3 kcal` `DeltaG = DeltaH - T DeltaS` `=3.3 xx -300 xx (0.02) =- 2.7 kcal`

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For the reaction, `X_(2)O_(4)(l)rarr2XO_(2)(g),DeltaE=2.1Kcal` , `DeltaS=20cal//K` at `300K` . Hence `DeltaG` isA. `2.7 kcal`B. `-2.7 kcal`C. `9.3 kcal`D. `-9.3 kcal`

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