For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance between a node and the next antinode isA. `7.5`B. `15`C. `22.5`D. `30`

For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance b

1.	For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance between a node and the next antinode isA. `7.5`B. `15`C. `22.5`D. `30`
Answer» Correct Answer - A Comparing given equation with standard equation `y=2asin.(2pix)/(lamda)cos.(2pivt)/(lamda)` gives us `(2pi)/(lamda)=(pi)/(15)implieslamda=30` distance between nearest node and antinodes `=(lamda)/(4)=(30)/(4)=7.5`.

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For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance between a node and the next antinode isA. `7.5`B. `15`C. `22.5`D. `30`

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