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For this reaction `N_(2(g))+3H_(2(g))to2NH_(3(g))` The relation between `(d(NH_(3)))/(dt)` and `-(d(H_(2)))/(dt)` is :-A. `-(1)/(3) (d[H_(2)])/(dt) = + (1)/(2) (d[NH_(3)])/(dt)`B. `-(1)/(2) (d[H_(2)])/(dt) = + (1)/(3) (d[NH_(3)])/(dt)`C. `+(1)/(2) (d[H_(2)])/(dt) = - (1)/(3) (d[NH_(3)])/(dt)`D. `+(1)/(3) (d[H_(2)])/(dt) = - (1)/(2) (d[NH_(3)])/(dt)`

Answer» Correct Answer - A


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