For traffic moving at `60km//h` if the radius of the curve is `0.1km` what is the correct angle of banking of the road Given `g = 10m//s^(2)` .

For traffic moving at `60km//h` if the radius of the curve is `0.1km`

1.	For traffic moving at `60km//h` if the radius of the curve is `0.1km` what is the correct angle of banking of the road Given `g = 10m//s^(2)` .
Answer» Correct Answer - `15.5^(@)`. Here, `upsilon = 60 km//h = (60 xx 1000)/(60 xx 60) m//s = (50)/(3) m//s` `r = 0.1 km = 100 m, theta = ? g = 10m//s^(2)` `tan theta = (upsilon^(2))/(rg) = (50)/(3) xx (1)/(100 xx 10) = 0.2777` `theta = tan^(-1) (0.2777) =15.5^(@)` .

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For traffic moving at `60km//h` if the radius of the curve is `0.1km` what is the correct angle of banking of the road Given `g = 10m//s^(2)` .

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