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For v->1 = 2i^ - 3j^ and v2-> = -6i^ + 5j^, determine the magnitude and direction of v1-> + v2-> ans: 2root5, theta= tan-1 (-1/2) with x axis |
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Answer» Answer:
.. 1 .. 12 Simple HARMONIC Motion 1. A particle executes simple harmonic motion with anamplitude of 10 cm and time period of 6 s. At time t = 0 it is at position = 5 going towards positive DIRECTION. Writethe equation for the displacement at time t. Find themagnitude of the ACCELERATION of the particle at time =4 . i) Given that amplitude A = 10 cm and time period T = 6sec. ⇒
ω = 2 π T = 2 π 6 = π 3 and =5 cm when = 0 ∴ 5 = 10
( + ) ⇒
= ½ ⇒
= /6 ∴ equation of displacement is = 10cm π t 3 + π 6 Explanation: |
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