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For what value (s) of x is `log_(10){999+sqrt(x^(2)-3x+3)}=3`? |
Answer» Correct Answer - D Given equation is : `log_(10){999+sqrt(x^(2)-3x+3)}=3` `implies999+sqrt(x^(2)-3x+3)=10^(3)=1000` `implies sqrt(x^(2)-3x+3)=1` `impliesx^(2)-3x+3=1` `x^(2)-3x+2=0` `impliesx^(2)-2x-x+2=0` `implies x(x-2)-1(x-2)=0` `implies (x-1)(x-2)=0` `implies x=1,2`. |
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